Pips Answer for Sunday, March 1, 2026
Complete NYT Pips puzzle solution with interactive board and expert analysis for Easy, Medium, and Hard difficulty levels.
Reveal by clicking a domino below OR a cell on the board
Expert Puzzle Analysis
Deep insights from puzzle experts
Nyt Pips easy answer for 2026-03-01
Answer for 2026-03-01
Solving today's Pips set was a real journey through logic and spatial reasoning. I started with the Easy puzzle, which felt like a warm-up exercise. The first thing I noticed was that sum region at (0,1) with a target of zero. That's a gift in Pips because it immediately locks that cell to a 0. Since (1,1) and (3,1) were empty, the layout was quite restricted.
I focused on the equals region involving (1,0), (2,0), (2,1), and (2,2). This meant those four cells had to have the same value. Looking at my domino list, the [2,2] jumped out at me because it's a double, and after testing some placements, the [3,0] had to fit near that zero I found earlier. Once the equals regions were satisfied, the rest of the dominoes like [5,2] and [3,6] fell into place like clockwork. Moving on to the
Nyt Pips medium answer for 2026-03-01
Answer for 2026-03-01
Medium puzzle, things got significantly more complex. Rodolfo Kurchan always likes to test your ability to balance multiple constraints. I looked for the most restrictive regions first. The sum of 0 at (4,0) was my anchor, telling me that specific cell had to be 0. Then I looked at the sum of 9 at (4,1) and (4,2).
In a standard domino set, a sum of 9 can only be 3+6 or 4+5. By cross-referencing this with the 'less than 4' constraint at (2,1), I could narrow down which dominoes belonged in the bottom rows. The equals region for (1,0), (2,0), and (3,0) was the real turning point. Finding a value that appeared on three different domino ends that could also satisfy the adjacent sums was the key. I eventually realized that using the 0 from the [4,0] domino and linking it up through the column was the only way to make the math work.
Nyt Pips hard answer for 2026-03-01
Answer for 2026-03-01
Finally, the Hard puzzle was a massive grid of single-cell targets. This felt more like a deduction game where I had to match the inventory of dominoes (the full 0-4 set) to the specific values requested in each cell. I started by marking all the 0 targets, as those are usually the easiest to place. The empty cells at (0,1), (1,4), (3,1), and others acted as buffers.
I noticed a cluster of high values like the 4s at (0,0), (0,4), and (4,0). Since I only had one [4,4] domino and a few others with 4s like [0,4], [1,4], [2,4], and [3,4], I had to be extremely careful not to 'waste' a 4 in the wrong spot. I worked from the corners inward, slowly connecting the dominoes like [1,5] and [2,5] (target 0 and 0) and the [4,4]/[4,5] pair at the bottom. It took a bit of back-and-forth, especially around the middle where the 0 and 1 targets were dense, but by keeping track of which dominoes I had already 'used' on my scratchpad, I managed to clear the board without any errors.
What I Learned
Today's puzzles really reinforced the importance of the 'domino inventory.' In the Hard puzzle especially, since it uses a specific set of dominoes (all combinations from 0 to 4), you can't just put numbers anywhere; you have to make sure the physical pieces actually exist. I learned that when you have multiple 'equals' regions or large 'sum' regions, it's often better to look at what numbers are NOT available rather than what are. For example, in the Medium puzzle, seeing a sum of 9 immediately limits your options to just two or three domino pairs.
Another tricky move was handling the empty cells. At first, they seem like dead space, but they actually tell you where a domino CANNOT go, which helps define the boundaries of the pieces you are trying to place. I also found that starting with the smallest sums (0s and 1s) and the largest sums (9s or 12s) is almost always the fastest way to build a foundation for the rest of the grid.